Can Uintptr_t be null?
The init member has integer type, it cannot be “made null”. You can assign 0 to it, or you can assign to it the result of converting a null pointer to uintptr_t . On almost every C implementation ever, those are the same thing.
Is null equal to null in C?
As for the first part of the question, yes, they are equivalent. The language standard actually states this explicitly somewhere — a pointer evaluates to true if it is non-NULL, and false if it is NULL, so the two are exactly identical.
What is IntPtr C#?
An IntPtr is an integer which is the same size as a pointer. You can use IntPtr to store a pointer value in a non-pointer type.
Is equal to null in C?
In practice, NULL is a constant equivalent to 0 , or “\0” . This is why you can set a string to NULL using: char *a_string = ‘\0’; Download my free C Handbook!
How does null work in C?
In computer programming, null is both a value and a pointer. Null is a built-in constant that has a value of zero. It is the same as the character 0 used to terminate strings in C. Null can also be the value of a pointer, which is the same as zero unless the CPU supports a special bit pattern for a null pointer.
What is IntPtr C++?
It is an integer that is the same size as a pointer. The IntPtr type can be used by languages that support pointers, and as a common means of referring to data between languages that do and do not support pointers. IntPtr objects can also be used to hold handles.
What is the difference between intptr and uintptr?
That is, an instance of this type is expected to be 32-bits on 32-bit hardware and operating systems, and 64-bits on 64-bit hardware and operating systems. The IntPtr type is CLS-compliant, while the UIntPtr type is not.
Why does the CLS use intptr instead of intptr?
The CLS is meant to operate cross-language. Some languages do not support unsigned types, which is why only signed types are considered CLS-compliant. So partly, IntPtr is used throughout the framework for that reason. Also, UIntPtr was only recently added.
What happens when you type a uint in C++?
Now once again, I’m no expert on the subject, but when you type cast something in C/C++ it doesn’t do any conversion to the memory allocated to the variable. It just makes the processor read the 32-bits (or 64.. whatever) at that memory location as a UINT instead of whatever it was typed as before. (Right?)
How to create a 64-bit pointer from a 32-bit int?
On a 64-bit system IntPtr is 64 bits wide. So assuming you have an Int64 variabled named “testLong” you could easily use “new IntPtr (testLong)” to create a 64-bit pointer from it. If you’re on a system where IntPtr is only 32-bits wide, then the .NET framwork can not address memory beyond the 32-bit pointer you initially had anyway.